Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Assume that impure copper contains only Fe, Au, Ag as impurities. After passing of 140 ampere for 482.5s, the mass of anode decreased by 22.260g and the cathode increased in mass by 22.011g. Calculate the percentage of iron and percentage of copper originally present.
THE increase in mass of cathode is due to deposition of Cu and the loss in mass of anode is due to loss of Cu and Feand loss of Ag and Au to fall in anode mudgain in weight at cathode due to copper=22.011gmole=22.011/63.5=.3466equivalent of Cu and Fe dissolved at anode=it/96500=140*482.5/96500=.70mole of Cu and Fe dissolved at anode=.7/2=.35mole of Fe=.3500-.3466=.0034weight of Fe dissolved at anode=.0034*56=.190gthus anode weight loss of 22.260g contains 22.011gCu,.19gFe,Au+Ag=.059g%Cu=22.011/22.26=98.88%%Fe=.190/22.26=.85%
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -