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Assume that impure copper contains only Fe, Au, Ag as impurities. After passing of 140 ampere for 482.5s, the mass of anode decreased by 22.260g and the cathode increased in mass by 22.011g. Calculate the percentage of iron and percentage of copper originally present. Assume that impure copper contains only Fe, Au, Ag as impurities. After passing of 140 ampere for 482.5s, the mass of anode decreased by 22.260g and the cathode increased in mass by 22.011g. Calculate the percentage of iron and percentage of copper originally present.
THE increase in mass of cathode is due to deposition of Cu and the loss in mass of anode is due to loss of Cu and Feand loss of Ag and Au to fall in anode mudgain in weight at cathode due to copper=22.011gmole=22.011/63.5=.3466equivalent of Cu and Fe dissolved at anode=it/96500=140*482.5/96500=.70mole of Cu and Fe dissolved at anode=.7/2=.35mole of Fe=.3500-.3466=.0034weight of Fe dissolved at anode=.0034*56=.190gthus anode weight loss of 22.260g contains 22.011gCu,.19gFe,Au+Ag=.059g%Cu=22.011/22.26=98.88%%Fe=.190/22.26=.85%
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