×

#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
Assume that impure copper contains only Fe, Au, Ag as impurities. After passing of 140 ampere for 482.5s, the mass of anode decreased by 22.260g and the cathode increased in mass by 22.011g. Calculate the percentage of iron and percentage of copper originally present.
Assume that impure copper contains only Fe, Au, Ag as impurities. After passing of 140 ampere for 482.5s, the mass of anode decreased by 22.260g and the cathode increased in mass by 22.011g. Calculate the percentage of iron and percentage of copper originally present.

```
6 years ago

Sunil Kumar FP
183 Points
```							Cu ---Cu+2 +2e-Fe ----Fe+2 +2e-gain in weight at cathode is due to deposition of Cu =22.011gMole of Cu deposited at cathode =22.011/63.5 =.3466equivalent of Cu and Fe dissolved at anode =it/96500 =140*482.5/96500 =.7moles of Cu and Fe dissolved at anode =.70/2 =.35mole of Fe dissolved at anode =.3500-.3466 =.0034weight of Fe dissolved at anode =.0034*56 =.190gmthus anode weigt loss of 220.260g contains 22.011g,.190gFe and Au+Ag =22.26-.190 =.059g%Cu=22.011/22.26 *100 =98.88%%Fe =.190/22.26*100 =.85%
```
6 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Physical Chemistry

View all Questions »

### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 141 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions