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Assume that impure copper contains only Fe, Au, Ag as impurities. After passing of 140 ampere for 482.5s, the mass of anode decreased by 22.260g and the cathode increased in mass by 22.011g. Calculate the percentage of iron and percentage of copper originally present.
Cu ---Cu+2 +2e-Fe ----Fe+2 +2e-gain in weight at cathode is due to deposition of Cu =22.011gMole of Cu deposited at cathode =22.011/63.5 =.3466equivalent of Cu and Fe dissolved at anode =it/96500 =140*482.5/96500 =.7moles of Cu and Fe dissolved at anode =.70/2 =.35mole of Fe dissolved at anode =.3500-.3466 =.0034weight of Fe dissolved at anode =.0034*56 =.190gmthus anode weigt loss of 220.260g contains 22.011g,.190gFe and Au+Ag =22.26-.190 =.059g%Cu=22.011/22.26 *100 =98.88%%Fe =.190/22.26*100 =.85%
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