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Grade: 8

                        

arrange the following in decreasing order of their bond length H 2 O, NH 3 ,H 2 S

4 years ago

Answers : (3)

Umakant biswal
5359 Points
							
@ rajiv 
the decreasing order will be 
H20 > h2s > nh3 
as the bond angle of h2s is smaller than that of h20 . 
and in case of h20 its 104 degree nearly and for ammonia is 101 degree nearly . 
IF U WANT REASON THEN LET ME KNOW 
ALL THE BEST ..
4 years ago
Sagar Gupta
39 Points
							The length of the bond is determined by the number of bonded electrons (the bond order). The higher the bond order, the stronger the pull between the two atoms and the shorter the bond length.Here we can compare with the bond order as here all atoms make single bond.So We know that the Bond Lenth is equal the the sum of the covalent radii between the two atoms.So here We knew Covalent Radii of H is 31,O is 66,N is 71 and  for S it`s 105. Remember it`s Single bond covalent radii.So for H20- it`s 31+66+31= 128For NH2- 164 and for H2S- 167So your order is H2S>NH2>H2O
						
4 years ago
rajiv
14 Points
							
both answers have confused me further as both are opposite to each other,can u recheck each others theory and let me know.thanks
4 years ago
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