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Grade: 12th pass
        
an organic compound containing Cand H gave the following analysis C=40%H=6.7% its emperical formula would be
3 months ago

Answers : (3)

Vikas TU
9095 Points
							
Hiiii 
Percentage of oxygen = 100 – (40+6.7 ) = 53.33
so it semperical formula = CH2O 
hope this helps
Regard
 
3 months ago
Saurabh Koranglekar
askIITians Faculty
3156 Points
							Dear student

I think question has some part missing ie remaining element being oxegen and its percentage being =53.7576-2351_Screenshot_2019-07-25-22-17-31-228_com.android.chrome.png
3 months ago
Sumit tiwari
15 Points
							
% of carbon = 40% & its Atomic mass =12 & its moles =40/12=3.33 & its simple ratio=1
% of Hydrogen=6.7% and it's Atomic mass=1 & its moles= 6.7/1=6.7 & its simple ratio = 2
% of oxygen = 53.3% & its Atomic mass= 16 & its  moles= 53.3/16=3.33 & its simple ratio= 1
.°. Empirical formula= CH2O
3 months ago
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