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An ionic compund AB has ZnS type of structure,if the radius of A+ is 22.5pm,then the ideal radius of B- is?

An ionic compund AB has ZnS type of structure,if the radius of A+ is 22.5pm,then the ideal radius of B- is?

Grade:12

1 Answers

Arun
25750 Points
5 years ago
Radius ratio = r+/r- = A+/B-
A+ = r+= radius of cation = 22.5 pm
B-  = r- = radius of anion = ?

Note-
AB has ZnS type of structure i.e AB has tetrahedral holes. Therefore, 

Radius ratio
= r+/r- =  A+/B- = 0.225
=> B- = A+ / 0.225 =  22.5 pm/0.225 = 100 pm

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