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An ionic compund AB has ZnS type of structure,if the radius of A+ is 22.5pm,then the ideal radius of B- is?
Radius ratio = r+/r- = A+/B-A+ = r+= radius of cation = 22.5 pmB- = r- = radius of anion = ?Note-AB has ZnS type of structure i.e AB has tetrahedral holes. Therefore, Radius ratio= r+/r- = A+/B- = 0.225=> B- = A+ / 0.225 = 22.5 pm/0.225 = 100 pm
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