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Here, NH4Cl has BCC cell structure and ions touch each other along the body diagonal of the cube.
Thus, 2r+ + 2r– =v3 a that is
2(r+ + 181 pm )= =v3 (387 pm)
(r+ = v3/2 (387 pm)–181 pm = 154.15 pm
The size of NH4+ ion is 154.15 pm
Thanks & Regards,
Vasantha Sivaraj,
askIITians faculty
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