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Grade: 12
        
  1. A zinc rod is placed in 0.095M zinc chloride solution at 25 degree C.emf of this cell is -0.79V.Calculate Ezn2+/zn.
     
3 years ago

Answers : (1)

Vikas TU
9764 Points
							
Apply formulae:
Reacn.:
Zn  ---------->         Zn 2+           +       2e-
Ecell = Ezn2+/zn – (0.0592/n)log90.095/1)
-0.79 = Ezn2+/zn –  (0.0592/2)log90.095/1)
Ezn2+/zn = -0.820 Volt
3 years ago
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