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A vessel of 120 ml capacity contains a certain amount of gas at 35C and 1.2 bar pressure. The gas is transferred to another vessel of volume 180 ml at 35C. What would be its pressure
Dear student According to Boyle’s Law P1 V1 = P2 V2Here the temperature is constant. Therefore1.2 X 120 = P2 X 180ORP2 = 1.2 X 120 /180 = 0.8 barTherefore, the pressure would be 0.8 bar.
According to Boyle’s Law P1 V1 = P2 V2
Here the temperature is constant. Therefore
1.2 X 120 = P2 X 180
P2 = 1.2 X 120 /180 = 0.8 bar
Therefore, the pressure would be 0.8 bar.
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