0

Guest

Courses New

a vessel contains equal volumes of SO2 and CH4. through a small hole, the gases effused into vacuum. After 200 sec, the total volume is reduced to half. what is the ratio of so2 and ch4 remaining in the vessel? 1)1:2 2) 2:1 3) 1:1 4) 1:4

a vessel contains equal volumes of SO2 and CH4. through a small hole, the gases effused into vacuum. After 200 sec, the total volume is reduced to half. what is the ratio of so2 and ch4 remaining in the vessel?
1)1:2    2) 2:1    3) 1:1    4) 1:4

Grade:12th pass

2 Answers

Arun
25750 Points
5 years ago
Dear student
 
I am getting my answer as 2:1
 
Please check
hope it helps
 
Regards
Arun (askIITians forum expert)
Salma wajid
15 Points
5 years ago
r1\r2=√m1 \m2 =√16\64 = 1\2
r1 \r2 =v1 \t1 × t2 \v2 
v1 \v2 = r1 \r2 = 1\2 (t1 =t2)
Out of three parts of the gas, 1part of so2 diffuses and 2parts of ch4 diffuses. So, the ratio left in the vessel is 2parts of so2 and 1 part of ch4. Thus the ratio of so2:ch4 is
2:1

Think You Can Provide A Better Answer ?

Other Related Questions on Physical Chemistry

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More