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Grade: 12th pass
        A vapour pressure aqueous solution of glucose is 750nm of hg and vapour prrssure of pure  water is 760nm of hg calculate the mole fraction of solute and molality of solution
10 months ago

Answers : (1)

BIKRAM
53 Points
							
This question is related to lowering of vapour pressure. Roult’s law P = X1×P0;here P= 750 nm of Hg , P0=760 nm of Hg
X1= (750/760)=0.987; Mole Fraction of solute (X2)=1-X1=0.013:
Molality = (0.013/0.987×18)×1000 = 0.73 (m)
10 months ago
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