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Grade: 12th pass
        A vapour pressure aqueous solution of glucose is 750nm of hg and vapour prrssure of pure  water is 760nm of hg calculate the mole fraction of solute and molality of solution
2 years ago

Answers : (1)

BIKRAM
53 Points
							
This question is related to lowering of vapour pressure. Roult’s law P = X1×P0;here P= 750 nm of Hg , P0=760 nm of Hg
X1= (750/760)=0.987; Mole Fraction of solute (X2)=1-X1=0.013:
Molality = (0.013/0.987×18)×1000 = 0.73 (m)
2 years ago
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