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Grade 12th passMechanics

A sphere of water of radius 1 mm is divided into two drops of radius r and 2r. Find out the change in surface energy. [ water 72dyne/cm  ]

Profile image of SOURAV MOLLA
6 Years agoGrade 12th pass
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1 Answer

Profile image of Vikas TU
6 Years ago
Dear student 
The change in surface energy is given by 
U = S* deltaA 
U = surface energy 
S = surface tension 
deltaA = Change in area
U = 72 * 4pi (4r^2 – r^2 ) 
U  = 72 * 4pi (3r^2) 
HHope this help 
Good Luck