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A solution with weight percentage of sodium hydroxide 6%is prepared by adding the following mass of water to 209g of that solution with the weight percent of sodium hydroxide of 30% find the amount of water to be added

Sainithi , 7 Years ago
Grade 8
anser 1 Answers
Aditya

Last Activity: 7 Years ago

w/W % = 30% (where w is weight of sodium and W is weight of solution)w/209 * 100 = 30w = 30 * 209/100w = 62.7w/(W + x) * 100 = 6 ( where x is mass of water)Substituting we get x = 836 gm

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