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Grade: 12th pass

                        

a solution of a 0.4g sample of H2O2 reacted with 0.632g of KMnO4 in the precence of sulphuric acid.calculate the percentage purity of the sample of H2O2.

5 years ago

Answers : (1)

Sakshi
askIITians Faculty
652 Points
							2KMnO4 + H202 = 2KOH + MnO2 +O2
According to the above reaction, 2 moles of KMnO4 react with H2O2 = 1 mol
158*2g KMnO4 react with H2O2 = 34g
0.632 g KMnO4 react with H2O2 = 34*0.632/(158*2)
= 0.068g
But according to the given ques, mass of H2O2 used for the reaction = 0.4 g
thus, the percentage purity is 0.068*100/0.4 = 17%
5 years ago
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