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A solution contains 2g of anhydrous bacl2 in 400cm3 it's conductivity is found to be 5.8*10-3 cm-1. Calculate the molar conductivity of bacl2 ( at. At.of bacl2 137)

one year ago

Vikas TU
9510 Points

Molar conductivity is given as: K x 1000/M
M is the molarity.
M = moles of solute / Volume of solution in litres. => (2/137)/(400/1000) => 20/(137*4) => 0.0634
Molar conductivity => 5.8*10-3 * 1000/0.0634 => 5.8/0.0634 => 91.48 Sm^2/mol.
one year ago
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