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Grade: 12
        
a solution contain NA2CO3 and NAHCO3.10ml of the solution required 2.5ml of 0.1M H2So4 for neutralisation using phenopthalein as indicator.Methyl orange is then added when a further 2.5ml of H2So4 was required.The amount of Na2Co3 and NaHCo3 in one litre of the solution is 
one month ago

Answers : (2)

Arun
22539 Points
							
According to the problem it requires 2.5 ml of 0.1 M H2SO4 for neutralization using phenolphthalein as indicator.  
0.0025 Litres of 0.1 mol / LItre H2SO4 = 0.00025 mol H2SO4  
by the reaction:  
1 H2SO4 & 2 (CO3)-2 --> 2 (HCO3)-1 & 1 (SO4)-2  
0.00025 mol H2SO4 reacts with twice as many moles of Na2CO3 = 0.00050 mol Na2CO3  
using molar mass, find grams  
( 0.00050 mol Na2CO3) (105.99 grams / mol Na2CO3) = 0.053 grams in the 10 ml sample  
The amount of Na2CO3 in 1 liter of solution is  
5.3 grams Na2CO3
 
one month ago
Vikas TU
8729 Points
							
Meq of Na2CO3 =1 
Meq of NaHCO3 =0.5
 For NaHCo3  alpha/84 *1000 = 0.5  
alpha = 0.042g
=> 4.2g/l 
Na2 Co3 =>>  Beta / 53 *1000 = 1
Beta = 5.3 g/l 
 
one month ago
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