#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.

Click to Chat

1800-5470-145

+91 7353221155

CART 0

• 0
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

# A mixture containing 2.24 L of H2 and 1.12 L of D2 at STP is taken inside bulb connected to another bulb by a stopcock with a small opening. The second bulb is fully evacuated, the stopcock is opened for a certain time and then closed. After effusion the 1st bulb contain 0.1 gm of D2. Find out the number of moles of H2 in second bulb

Grade:11

## 1 Answers

Arun
25763 Points
3 years ago
1 mol occupies 22.4 litre of volume.
% mole of H2 = 2.24/22.4 = 0.01 mole
Mass of H2 = 2* 0.01 = 0.02 gm
Similarly, moles of D2 = 1.12/22.4 = 0.05 mole
Mass of D2 = 4* 0.05 = 0.2 gm

Now as 0.1 gm of H2 remains in 1st bulb
Hence
O.1 gm of H2 will remain in 2nd bulb and 0.2 gm of D2 in second bulb also.
Weight % of H2 = 0.1/(0.1+0.2) = 0.1/0.3 = 1/3 = 33.33%

Hence % of D2 = 100- 33.33 = 66.67 %

## ASK QUESTION

Get your questions answered by the expert for free