0

Guest

Courses New

A metal crystallises into a lattice containing sequence of layers of ABC-ABC....If the radius of metal atoms is 174pm then the distance between two successive layers that is A and B is? (a) 348 pm (b) 174 pm (c) 284.2 pm (d) 492.2 pm

A metal crystallises into a lattice containing sequence of layers of ABC-ABC....If the radius of metal atoms is 174pm then the distance between two successive layers that is A and B is?
(a) 348 pm
(b) 174 pm
(c) 284.2 pm
(d) 492.2 pm

Grade:12

1 Answers

ats
103 Points
3 years ago
The metal has cubic close packed (ccp) lattice as the sequence of layers is ABC-ABC.
The radius  r of the metal atom is 174 pm.
For ccp lattice,
       Side lenght of unit cell (a) = 4 x 174 / sqrt(2)                  [ sqrt(2) x a/4 =r
                                                 = 492.15 pm                            Hence, a = 4 x r /sqrt(2) ]
Distance between layer A and B = a/sqrt(3)
                                                 = 284.2 pm approximately
 
So the answer is © 284.2 pm.
 
Hope it helps! Pls approve if you found it useful.
All the best for your preparation!
 
 

Think You Can Provide A Better Answer ?

Other Related Questions on Physical Chemistry

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More