badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11

                        

A light source of frequency 6 × 10^15 Hz is subjected to a metal sheet having work function equal to 22.6 eV . Then , the velocity of photo-electrons emitted having maximum kinetic energy will be. 1) 4.43 * 10^5 m/s 2) 3.21 * 10^7 m/s 3) 8.89 * 10^5 m/s 4) 8.73 * 10^6 m/s

2 years ago

Answers : (1)

Paarth Chhabra
26 Points
							
hv= 6.626×6x10-¹²x10-⁴x10-³
= 39.756x10^-19 
~ 39.76 x 10^-19
 
hv°= 22.6×1.6x10^-19
= 36.16x 10^-19
 
hv=hv°+1/2mv²
1/2mv²= hv-hv° = 3.6 x10^-19
9.1x10^-31 x v² = 7.2 x 10^-19
v² = (7.2/9.1)x 10¹²
v = 0.889 x 10^6 = 8.89 x 10^5
 
Hence 3)
2 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 141 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details