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A light source of frequency 6 × 10^15 Hz is subjected to a metal sheet having work function equal to 22.6 eV . Then , the velocity of photo-electrons emitted having maximum kinetic energy will be. 1) 4.43 * 10^5 m/s2) 3.21 * 10^7 m/s3) 8.89 * 10^5 m/s4) 8.73 * 10^6 m/s
hv= 6.626×6x10-¹²x10-⁴x10-³= 39.756x10^-19 ~ 39.76 x 10^-19 hv°= 22.6×1.6x10^-19= 36.16x 10^-19 hv=hv°+1/2mv²1/2mv²= hv-hv° = 3.6 x10^-199.1x10^-31 x v² = 7.2 x 10^-19v² = (7.2/9.1)x 10¹²v = 0.889 x 10^6 = 8.89 x 10^5 Hence 3)
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