Join now for JEE/NEET and also prepare for Boards Join now for JEE/NEET and also prepare for Boards. Register Now
Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
(a) H2O2 + 2H+ + 2I- ? I3- + 2H2O; The equality in this case is -d[H2 O2 ]/dt = -1/2 d[H+ ]/dt = -1/2 d[I3- ]/dt = 1/2 d[H2O]/dt So, -d[I- ]/dt = -3d[H2 O2 ]/dt = -3/2 d[H+]/dt = 3d[I3- ]/dt = 3/2 d[H2O]/dt how is 3 coming as the coefficient in -3d[H2O2]/dt (a) H2O2 + 2H+ + 2I- ? I3- + 2H2O;The equality in this case is-d[H2 O2 ]/dt = -1/2 d[H+ ]/dt = -1/2 d[I3- ]/dt = 1/2 d[H2O]/dtSo, -d[I- ]/dt = -3d[H2 O2 ]/dt = -3/2 d[H+]/dt = 3d[I3- ]/dt = 3/2 d[H2O]/dthow is 3 coming as the coefficient in -3d[H2O2]/dt
For the equation:H2O2 + 2H+ + 2I---> I3- + 2H2OThe equality should be:-d[I- ]/dt = -2d[H2 O2 ]/dt = - d[H+]/dt = 2d[I3- ]/dt = d[H2O]/dtThanks and RegardsPankaj SinghaskIITians Faculty
For the equation:
H2O2 + 2H+ + 2I---> I3- + 2H2OThe equality should be:-d[I- ]/dt = -2d[H2 O2 ]/dt = - d[H+]/dt = 2d[I3- ]/dt = d[H2O]/dt
Thanks and Regards
Pankaj Singh
askIITians Faculty
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -