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Grade:

                        

A first order reaction is carried out with an initial concentration of 10 mol per litre and 80% of the reactant changes into the product. Now if the same reaction is carried out with an initial concentration of 5 mol/L for the same period the % of th reactant changing to the product is- a.40 b.80 c.160

2 years ago

Answers : (1)

Arun
25333 Points
							
Dear Tanusri
 
 
For the 10ML-1 concentration,
k = ln(10/2)/t.....(1)
and
for 5ML-1
k = ln(5/x)/t..............(2)
From both the eqns. we get,
5 = 5/x
x = 1
that means % that gets converted to product, 
4*100/5 => 80%
 
 
Regards
Arun (askIITians forum expert)
2 years ago
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