Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
A first order reaction has a half life of 14.5 hours. What percentage of the reactant will remain after 24 hours?
[A] = [Aº] x e^(-kt) first, find k half life = 0.693/k 14.5hours = 0.693/k k = 0.048 second, solve for [A] [A] = 1M x e^(-0.048 x 24) [A] = 0.316M 31.6%
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -