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A first order reaction has a half life of 14.5 hours. What percentage of the reactant will remain after 24 hours? A first order reaction has a half life of 14.5 hours. What percentage of the reactant will remain after 24 hours?
[A] = [Aº] x e^(-kt) first, find k half life = 0.693/k 14.5hours = 0.693/k k = 0.048 second, solve for [A] [A] = 1M x e^(-0.048 x 24) [A] = 0.316M 31.6%
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