×

#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

a fan rotating 100 rad/sec is switched off after 2n rotation its angular velocity becomes 50 rad/sec find its angular velocity after n revolution


2 years ago

## Answers : (1)

Eshan
2095 Points
							Dear student,Angular displacement in 2n rotations is$\dpi{80} 4n\pi$.Hence from equation of motion,$\dpi{80} \omega^2-\omega_0^2=2\theta \alpha$$\dpi{80} \implies \alpha=\dfrac{50^2-100^2}{2(2n\pi)}=-\dfrac{7500}{8n\pi}$Hence angular velocity after n rotations=$\dpi{80} \sqrt{\omega_0^2+2\alpha\theta_2}=\sqrt{100^2-2\dfrac{7500}{8n\pi}(2n\pi)}=79rad/sec$

2 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

## Other Related Questions on Physical Chemistry

View all Questions »

### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 141 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions