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A current of 0.5 Ampere strength passing through AgNO3 solution for 6 minutes deposits 0.2013 gram of Ag. What is the electrical conductivity of Ag?

Vj Sharma , 8 Years ago
Grade 12th pass
anser 1 Answers
Vikas TU

Last Activity: 8 Years ago

From Faraday’s first law that is:
mass = Z x Q
we get,
Z = mass/Q = > 0.2013/(0.5*6) => 0.2013/3 => 0.0671
 

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