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A compound has a haemoglobin like structure.It has one Fe.It contain 4.6% of Fe. Determine it’s molecular mass.
let M be the molecular mass of Haemoglobin.which contains one Fe atom.then % of Fe in Haemoglobin =>4.6% = (1*56/x) * 100%Solving for x we get,x = 1217.39 g
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