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A certain organic substance used as a solvent in many reactions contains carbon, hydrogen, oxygen and sulphur. Weight % of hydrogen in the compound is 7.7. The weight ratio C:O:S = 3:2:4, What is the least possible molar mass (in g) of the compound ?
Let x be the no. of H atoms in the compund then,{ (1*x)/(1*x + 3*12 + 2*16 + 4*32) } * 100 = 7.7solving for x we get,x = 1509.2/92.3 = > 16.35Total molecular mass = > 16.35*1 + 3*12 + 2*16 + 4*32 = > 212.35 g
Anurag singh Hello friends, Mass of %hydrogen=7.7 simplest ratio =6Mass of %carbon=30.4. Simplest ratio=2Mass of %oxygen=20.52. Simplest ratio =1Mass of %sulphur =41.04. Simplest ratio =1 The empirical formula is C2H6OS by going by the steps the simplest ratio will help you The molar mass of the compound =2*12+6*1+16+32=78Here is the answer .good luck for exams.....
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