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Grade: 11
        
A 40 ml sample of an aqueous solution of the methylamine at 25ºC is titrated with 0.15 M HCl and the equivalence point is reached when 40 ml of the acid have been added. The pH at the equivalence point is
2 years ago

Answers : (1)

Vikas TU
9795 Points
							
Equivalent Weight of the methylamine = Eq. Weight of the Hcl titrated.
Therefore,
M x V x V.F =M x V. V.f.
0.15 x 40 x 1 = M x 40 x 1
M  = 0 .15
From pH = pKa + log (base/acid) 
pH can be determined.
as pKa is not provide the data is insufficient here to further calculate the pH.
Therfore plz do check the qstn. and provide the necessary things. 
2 years ago
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