A 2.24L cylinder of oxygen at N.T.P is found to develop a leakage. When the leakage was plugged the pressure dropped to 570mmof Hg. The number of moles of gas that escaped will be- A) 0.025 B) 0.050 C) 0.075 D) 0.09

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Arun · Answer

Original pressure of Hg= 760 drop in pressure= 570 change in pressure= 760-570= 190mm = 190/760 atm PV= nRT n = P V/ RT = 190 x 2.24/ 760 x 0.821 x 273 = 0.0249 moles

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A 2.24L cylinder of oxygen at N.T.P is found to develop a leakage. When the leakage was plugged the pressure dropped to 570mmof Hg. The number of moles of gas that escaped will be- A) 0.025 B) 0.050 C) 0.075 D) 0.09

A 2.24L cylinder of oxygen at N.T.P is found to develop a leakage. When the leakage was plugged the pressure dropped to 570mmof Hg. The number of moles of gas that escaped will be-
A) 0.025
B) 0.050
C) 0.075
D) 0.09

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A 2.24L cylinder of oxygen at N.T.P is found to develop a leakage. When the leakage was plugged the pressure dropped to 570mmof Hg. The number of moles of gas that escaped will be- A) 0.025 B) 0.050 C) 0.075 D) 0.09

A 2.24L cylinder of oxygen at N.T.P is found to develop a leakage. When the leakage was plugged the pressure dropped to 570mmof Hg. The number of moles of gas that escaped will be-A) 0.025B) 0.050C) 0.075D) 0.09

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A 2.24L cylinder of oxygen at N.T.P is found to develop a leakage. When the leakage was plugged the pressure dropped to 570mmof Hg. The number of moles of gas that escaped will be-
A) 0.025
B) 0.050
C) 0.075
D) 0.09