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A 2.24L cylinder of oxygen at N.T.P is found to develop a leakage. When the leakage was plugged the pressure dropped to 570mmof Hg. The number of moles of gas that escaped will be- A) 0.025 B) 0.050 C) 0.075 D) 0.09
Original pressure of Hg= 760drop in pressure= 570change in pressure= 760-570= 190mm= 190/760 atmPV= nRTn = P V/ RT= 190 x 2.24/ 760 x 0.821 x 273 = 0.0249 moles
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