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Given:-Mass of CaSO4 = 0.24gVolume of solution = 100 mlKsp of CaSO4 = ?solution :-CaSO4 will dissociates in the following way:-CaSO4 ---------> Ca2+ + SO42-thus,Ksp = [Ca2+] + [SO42-] now to calculate the solubility of CaSO4,as it can be expressed on moles/litrefirst we calculate the no. of moles of CaSO4 = Mass of CaSO4 = 0.24Molar mass of CaSO4 136thus no. of moles = 0.00176 or 0.0018now solubility in no. of moles/litre = 0.0018 * 10000 = 0.018moles/litre100thus CaSO4 on dissociation will give 0.018 mole of Ca ions as well 0.018 moles of SO4ionsKsp= [0.018]*[0.018] = 0.00032 or 3.2* 10 to the power -4.Thanks & regardAarti Guptaaskiitians Faculty
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