6 g he and 12g ne molecules both have average velocity 4 *10 raised to power 2 m/s are mixed .find kinetic energy per mole of the mixture
AKASH , 7 Years ago
Grade 12th pass
1 Answers
Vikas TU
Last Activity: 5 Years ago
Dear student Total number of moles of the mixture = Moles of He + Moles of Ne = 6/4 + 12/20 = 2.10 Kinetic energy per mole of system = 1/2(mass of He + mass of neon)*v^2 * 2.10 => 2.1 * 1/2 (18)* 16*10^4 => 302.4 * 10^4 J Hope this helps
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