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500 mL of 56V H2O2 is kept in an open container due to which some H2O2 is decomposed and evolves 8gm O2 simultaneously, during the process some H2O also vapourizes.Due to all these changes final volume is reduced by 20%. Find final volume strength of H2O2 (aq).
500 mL of 56V H2O2 is kept in an open container due to which some H2O2 is decomposed and evolves 8gm O2 simultaneously, during the process some H2O also vapourizes.Due to all these changes final volume is reduced by 20%. Find final volume strength of H2O2 (aq).

```
3 years ago

Mrinali
13 Points
```							Vol strength= 56VVol of O2 produced by 500ml solution = 56*500 = 28 Lt.Moles of O2 produced = 28/22.4 = 1.25 mol1mol of O2 produced by 2mol H2O2 => 1.25 mol of O2 produced by 2.5 mol of H2O2So, mass of H2O2 = 2.5*34= 85gDensity= 170g/LtO2 escaped= 8g or 0.25 molHence 0.5 mol of H2O2 decomposes to produce 0.5 mol of H2O n 0.25 mol of O2Loss = 20% of 85g  = mass of O2 escaped+ mass of H2O vapourised=> mass of H2O vapourised = 17 - 8 = 9gSo final solution contains only H2O2Mass of final solution = 85 - 17 = 68gFinal vol = 68/170 = 400ml68g H2O2 gives 32g O2=> 400ml of solution gives 1mol of O2 or 22400ml O2=> 1ml solution gives = 22400/400= 56ml of O2Hence vol strength = 56V
```
2 years ago
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