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Grade: 10
        
5 ml of a gas containing only carbon and hydrogen were mixed with an excess of oxygen (30 ml) and the mixture exploded by means of an electric spark. After the explosion, the volume of the mixed gases remaining was 25 ml. on adding a concentrated solution of potassium hydroxide, the volume further diminished to 15 ml of the residual gas being pure oxygen. All volumes have been reduced to N.T.P. Calculate the molecular formula of the hydrocarbon gas.
5 years ago

Answers : (1)

Jitender Pal
askIITians Faculty
365 Points
							
Volume of oxygen taken = 30 ml
Volume of unused oxygen = 15 ml
Volume of O2 used = Volume of O2 added – Volume of O2 left
= 30 – 15 = 15 ml
Volume of CO2 produced
= Volume of gaseous mixture after explosion – Volume of unused oxygen
Or Volume of CO2produced = 25 – 15 = 10 ml
Volume of hydrocarbon = 5 m;
General equation for combustion of a hydrocarbon is as follows –
CxHy + (x + y/4)
O2 → xCO2 +y/4 H2O
(Hydrocarbon)
5 ml 5(x + y/4)ml 5 x
∴ Volume of CO2 produced = 5x, Since Volume of CO2 = 10 ml
∴ 5x = ⇒ x = 2, Volume of O2 used = ml
∴ 5 (x + y/4) = 15 ⇒ x + y/4 = 3
⇒ 2 + y/4 = 3 (∵ x = 2)
⇒ 8 + y = 12 ∴ y = 4
5 years ago
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