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45g of alloy is heated to a temperature of 90°C and dropped in 82g of water at temp 396.5 k.The temperature of water rises to 399.5 k ,given that the specific heat of water is 1Cal K-1 g-1 .Calculate the T1 of alloy and specific heat of alloy

Sabit , 6 Years ago
Grade 11
anser 1 Answers
Arun

Last Activity: 6 Years ago

Dear Sabit
 
As we know – 
 
Q = mc(T2 – T1)
heat loss = heat gain
45*c*(399.5 – 363) = 82*1*(399.5 – 396.5)
So c = 0.15 Cal K-1g-1
 
Regards
Arun (askIITians forum expert)

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