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`        3 moles of A and 4 moles of B are mixed together and allowed to come into equilibrium according to the following reaction.            3A(g) + 4B(g) = 2C(g) +3D(g) when equilibrium is reached, There is 1 mole of C. The equilibrium constant of the reaction is 	  1÷4	   1÷3	    1÷2	     1​Please explain in deail............... `
9 months ago

Arun
22540 Points
```							tDear student I think that you have typed a wrong question. Please check all the reaction as I am not getting answer  as the options are. You can also attachan image. I will be happy to help you.
```
9 months ago
Arun
22540 Points
```							Dear student it has been solved, all thing is correct solution  3A + 4 B = 2C + 3 D at equilibrium3- 3x  4- 4x    2x     3x as 2x = 1x = ½ now equilibrium constant = 6x^2 / (3- 3x) (4-4x) = 6/4 / 3 = 2/4 = ½ hence option C is correct
```
9 months ago
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### Course Features

• 141 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions