3 L of N 2 gas are mixed with 6 L of H 2 gas to form NH 3 gas. What volume of NH 3 gas can be produced, if all volumes are measured under same temperature and pressure conditions?

Question

sree lakshmi · Answer

The balanced equation N 2 +3H 2 =2NH 3 Volume of 1mol gas molecule is 22.4L according to Avogadros law law stating that equal volumes of gases at the same temperature and pressure contain equal numbers of molecules. so 3×22.4 L hydrogen gives 2×22.4 L ammonia Then 6L hydrogen ---> x L ammonia x =6×(2×22.4) / (3×22.4) x= 4L ie. The reaction gives 4L of NH 3

Saurabh Koranglekar · Answer

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3 L of N 2 gas are mixed with 6 L of H 2 gas to form NH 3 gas. What volume of NH 3 gas can be produced, if all volumes are measured under same temperature and pressure conditions?

3 L of N₂ gas are mixed with 6 L of H₂ gas to form NH₃ gas. What volume of NH₃ gas can be produced, if all volumes are measured under same temperature and pressure conditions?

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3 L of N 2 gas are mixed with 6 L of H 2 gas to form NH 3 gas. What volume of NH 3 gas can be produced, if all volumes are measured under same temperature and pressure conditions?

3 L of N2 gas are mixed with 6 L of H2 gas to form NH3 gas. What volume of NH3 gas can be produced, if all volumes are measured under same temperature and pressure conditions?

2 Answers

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3 L of N₂ gas are mixed with 6 L of H₂ gas to form NH₃ gas. What volume of NH₃ gas can be produced, if all volumes are measured under same temperature and pressure conditions?