Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        2 moles of N2 is mixed with 6 moles of H2 ina closed vessel of 1 litre capacity .If 50%N2 is converted into NH3 at equilibrium,the value of kc for the reaction:-N2(g)+3H2(g)------>2NH3(g)`
2 years ago

Arun
23523 Points
```							Dear student N2 (g) + 3H2 (g) → 2 NH3(g)Initial 1mole (given) 3 mole (given) 0At equilibrium 1-(0.25 * 1)/100 3--(0.25 * 1)/100 2(0.25 * 1)/1000.9975 moles 2.9925 moles 0.005 moles Given that 0.25% of nitrogen is converted to ammonia (given) therefore 1-0.25% is doneKc = [NH3]2/[N2][H2]3 = (0.005/4)2/(2.9925/4)(0.9975/4)3 = 1.8 * 10-8 RegardsArun (askIITians forum expert)
```
2 years ago
Berjees shah
19 Points
```							N2 + H2 2NH3.     Initial moles = 2.  6.   0At equilibrium 2(1-x). 6(1-3x).  2xKc =[1]÷[1]×[3]=1÷27 ans....
```
2 years ago
nishant kumar
36 Points
```								allwrong above this becaues coreect answer is jai ho goglle baba . jai ho jai ho goglee baba ki jai ho
```
one year ago
nishant kumar
36 Points
```							 N2 (g) + 3H2 (g) → 2 NH3(g)Initial 1mole (given) 3 mole (given) 0At equilibrium 1-(0.25 * 1)/100 3--(0.25 * 1)/100 2(0.25 * 1)/1000.9975 moles 2.9925 moles 0.005 moles Given that 0.25% of nitrogen is converted to ammonia (given) therefore 1-0.25% is doneKc = [NH3]2/[N2][H2]3 = (0.005/4)2/(2.9925/4)(0.9975/4)3 = 1.8 * 10-8
```
one year ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Physical Chemistry

View all Questions »

### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 141 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions