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Grade: 12th pass
        2 moles of N2 is mixed with 6 moles of H2 ina closed vessel of 1 litre capacity .If 50%N2 is converted into NH3 at equilibrium,the value of kc for the reaction:-N2(g)+3H2(g)------>2NH3(g)
one year ago

Answers : (4)

Arun
23036 Points
							
Dear student
 

N(g) + 3H2 (g)  2 NH3(g)

Initial 1mole (given) 3 mole (given) 0

At equilibrium 1-(0.25 * 1)/100 3--(0.25 * 1)/100 2(0.25 * 1)/100

0.9975 moles 2.9925 moles 0.005 moles

 

Given that 0.25% of nitrogen is converted to ammonia (given) therefore 1-0.25% is done

Kc = [NH3]2/[N2][H2]3 = (0.005/4)2/(2.9925/4)(0.9975/4)3 = 1.8 * 10-8

 

Regards

Arun (askIITians forum expert)

one year ago
Berjees shah
19 Points
							N2 + H2 2NH3.     Initial moles = 2.  6.   0At equilibrium 2(1-x). 6(1-3x).  2xKc =[1]÷[1]×[3]=1÷27 ans....
						
one year ago
nishant kumar
36 Points
							
  • allwrong above this becaues coreect answer is jai ho goglle baba . jai ho jai ho goglee baba ki jai ho
one year ago
nishant kumar
36 Points
							
 

N(g) + 3H2 (g)  2 NH3(g)

Initial 1mole (given) 3 mole (given) 0

At equilibrium 1-(0.25 * 1)/100 3--(0.25 * 1)/100 2(0.25 * 1)/100

0.9975 moles 2.9925 moles 0.005 moles

 

Given that 0.25% of nitrogen is converted to ammonia (given) therefore 1-0.25% is done

Kc = [NH3]2/[N2][H2]3 = (0.005/4)2/(2.9925/4)(0.9975/4)3 = 1.8 * 10-8

one year ago
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