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`        2 g of a substance dissoled in 40 g of water produced a depression of 274.5 k in the freezing point of water. Calculate the molecular mass of the substance. The molal depression constant for water is 274.85 k per molal.`
one year ago

Labanya
11 Points
```							w2(solute)=2g w1(water)= 40g kf= 274.85 kkgmol^-1 delTf= 274.5k m2=?therefore, we knowdelTf=kf×molalitydelTf= kf× 1000×w2/(M2*w1)M2=kf*1000*w2/(delTf*w1)M2= 274.85×1000×2/(274.5×40)M2= 50.06 gmol^-1
```
one year ago
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