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```        2.76 g of silver carbonate on being strongly heated yields a residue weighing
a. 2.16 g
b. 2.48 g
c. 2.32 g
d. 2.64 g
```
3 years ago

Jitender Pal
365 Points
```										Sol. Unlike other metal carbonates that usually decomposes into metal oxides liberating carbon dioxide, silver carbonate on heating decomposes into elemental silver liberating mixture of carbon dioxide and oxygen gas as
Ag2CO3 (s)   2Ag (s) + CO2 (g) + 1/2 O2 (g)
MW = 276g  2 × 108 = 216 g
Hence, 2.76 g of Ag2CO3 on heating will give
216/276× 2.76 = 2.16 g Ag as residue.

```
3 years ago
Ayushman Singh
14 Points
```										the rxn is as follows Ag2CO3=Ag + Co2 + O2    No need to balance the equation   just apply POAC.  2×moles of Ag2Co3= 1× Mole of Ag   and moles = Weight in gram/molr mass put the values and u will get the same answer. POAC is very simple just conserve the no of atoms of that particular element on both the sides and get the answer.
```
10 months ago
Janki
19 Points
```										Here, First write the equation..Ag2CO3 --------》 2Ag + CO2 + 1/2 O2263.6g                   203.6g           (standard molecular wt)But, Ag2CO3=2.76gSo, 263.6g Ag2CO3   ------   203.6g 2Ag      2.76g Ag2CO3.     -----  ?So, 2.76 × 203.6/263.6      =2.13g      ~2.16gHope it helped! :)
```
8 months ago
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