2.12 g mixture of hexanoic acid and octanoic acid was dissolved in 100 ml of water and its 10 ml portion required 16.67 ml of a 0.1M standard alkali solution. determine the percentage composition of the mixture.

Question

Sarthak gupta · Answer

Equivalents of Mixture is equal to equivalents of alkali medium Let Hexanoic Acid be X gm and Octanoic Acid be 2.12 - X gm in mixture. X / 116 * 1 = 2.12 - X /144 * 1 = 16.67 * 0.1 / 1000 X = 0.193 Hexanoic Acid - 9.1 % Octanoic Acid -. 90.9 %

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2.12 g mixture of hexanoic acid and octanoic acid was dissolved in 100 ml of water and its 10 ml portion required 16.67 ml of a 0.1M standard alkali solution. determine the percentage composition of the mixture.

2.12 g mixture of hexanoic acid and octanoic acid was dissolved in 100 ml of water and its 10 ml portion required 16.67 ml of a 0.1M standard alkali solution. determine the percentage composition of the mixture.

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2.12 g mixture of hexanoic acid and octanoic acid was dissolved in 100 ml of water and its 10 ml portion required 16.67 ml of a 0.1M standard alkali solution. determine the percentage composition of the mixture.

2.12 g mixture of hexanoic acid and octanoic acid was dissolved in 100 ml of water and its 10 ml portion required 16.67 ml of a 0.1M standard alkali solution. determine the percentage composition of the mixture.

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