badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12

                        

2.12 g mixture of hexanoic acid and octanoic acid was dissolved in 100 ml of water and its 10 ml portion required 16.67 ml of a 0.1M standard alkali solution. determine the percentage composition of the mixture.

4 months ago

Answers : (1)

Sarthak gupta
15 Points
							
Equivalents of Mixture is equal to equivalents of alkali medium
Let Hexanoic Acid be X gm and Octanoic Acid be 2.12 - X gm in mixture.
X / 116 * 1 = 2.12 - X /144 * 1 = 16.67 * 0.1 / 1000
X = 0.193
Hexanoic Acid -     9.1 %
Octanoic Acid -.      90.9 %
4 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 141 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details