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how much energy is emitted out when amole of electron falls in 1g
atom of H atom II to I orbit?
Rh=109678 cm-1
Dear Yash Jain,
Ans:- We know that
1/λ = Rh(1/(n1)² - 1/(n2)²)
putting n1=1 n2=2 and Rh as given, we get the value of λ. Then find energy putting E=hc/λ
Then multiply it with the Avogadro number and get the total energy
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Regards,
Askiitians ExpertsSoumyajit Das IIT Kharagpur
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