how much energy is emitted out when amole of electron falls in 1gatom of H atom II to I orbit?Rh=109678 cm-1

Dear Yash Jain,

Ans:- We know that

1/λ = Rh(1/(n1)² - 1/(n2)²)

putting n1=1 n2=2 and Rh as given, we get the value of λ. Then find energy putting E=hc/λ

Then multiply it with the Avogadro number and get the total energy

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