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a solution is prepared by dissolving 516.5mg of oxalic acid to make 100ml of solution.A 10ml portion is then diluted to 250ml.what is the molarity of the final solution.

a solution is prepared by dissolving 516.5mg of oxalic acid to make 100ml of solution.A 10ml portion is then diluted to 250ml.what is the molarity of the final solution.

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1 Answers

Gaurav
askIITians Faculty 164 Points
8 years ago
.5165 g x (1mole)/(90g) = number of moles= .0057388

Molarity=.0057388moles/.1liters=.05738... solution

(.057388 moles/liter) X (10ml/250ml)=.002295
On calculating we get correct solution as0.02M

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