MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade:
        

Find the oxidation number of carbon in the following compounds:


CH3OH, CH2O , HCOOH , C2H2.

9 years ago

Answers : (1)

askIITIians Expert
21 Points
							

Solution:

In all these compounds H has oxidation number +1 and O has oxidation number -2. Using rule 3 (d) the values of o.n of carbon in each of the above compounds can be determined using the following general method.

If the number of hydrogen atoms in the compounds is nH, the number of oxygen atom is nO and the number of carbon atoms is nC then we have:

nH(1) + nO (-2) + nC (o.n. of carbon) = 0

or o.n. of carbon in the compound = (nO (2) - nH (1) /nC

The results for different compounds are given in table below:

Compound

nH

nO

nC

o.n. of C = (no x2 – nH )/nC

CH4

4

0

1

-4

CH3OH

4

1

1

-2

CH2O

2

1

1

 0

HCOOH

2

2

1

+2

C2H4

4

0

2

-2

C2H2

2

0

2

-1

9 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 141 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details