Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
Find the oxidation number of carbon in the following compounds:
CH3OH, CH2O , HCOOH , C2H2.
Solution:
In all these compounds H has oxidation number +1 and O has oxidation number -2. Using rule 3 (d) the values of o.n of carbon in each of the above compounds can be determined using the following general method.
If the number of hydrogen atoms in the compounds is nH, the number of oxygen atom is nO and the number of carbon atoms is nC then we have:
nH(1) + nO (-2) + nC (o.n. of carbon) = 0
or o.n. of carbon in the compound = (nO (2) - nH (1) /nC
The results for different compounds are given in table below:
Compound
nH
nO
nC
o.n. of C = (no x2 – nH )/nC
CH4
4
0
1
-4
CH3OH
-2
CH2O
2
HCOOH
+2
C2H4
C2H2
-1
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !