determine the dgree of disociation of 0.05 m NH3 at 250 in a solution of ph=11
tejas sanjay akole , 16 Years ago
Grade 12
1 Answers
Sunil Kumar FP
nh3 + h2o----nh4+ oh- let the degree of dissociation be x nh3=.05-.05x nh4+= .05x oh- =10^-3 +.05x value of k not given find x from this eqn= k=.05x(10^-3 +.05x)/.05(1-x)
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