Flag Physical Chemistry> chemical kinetics...
question mark

dear vishal sir itz ok formula wise but my real ques was that if 5 nuclie are present then after 1 half life there should be 2.5 nuclie but thats impposible so it should not be 2.5 what it should be?and if not 2.5 why we call it half life

puneet dwivedi , 14 Years ago
Grade
anser 1 Answers
Askiitians Expert Bharath-IITD

Last Activity: 14 Years ago

Dear Puneet,

The formula that we use to calculate the half time is t = ln 2 / λ has many approximations. First approximation is the value of ln 2 which is usually taken as 0.693 which is only an approximate value and the decay constant usually measured from the experiments are also approximate. And thus the value of half time we get is also an approximate value. The concept of half life essentially an aid for understanding the phenomena of radioactive deacay of aprent nucleus. Also it has some applications like that of carbon dating and uranium dating for determinig the ages of organic matters and the age of the earth. Also the values of the half life are in the orders of usally thousands of years in these applications. Another important thing is that there are no such thing as 5 atoms , usually in all radioactivity measurements they are present in the orders of millions  atleast. Dont look at the concept as a simple mathematical concept.

 

Please feel free to post as many doubts on our discussion forum as you can. If you find any question
Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We
are all IITians and here to help you in your IIT JEE preparation.


All the best  !!!

 


Regards,

Askiitians Experts

Adapa Bharath
 

Provide a better Answer & Earn Cool Goodies

Enter text here...
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments


Ask a Doubt

Get your questions answered by the expert for free

Enter text here...