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The number of moles of Br2 produced when two moles of potassium permanganate are treated with excess potassium bromide in aqueous acid medium is :
KMno4 + KBr -----> Mn2+ + Br2
2 mole excess
number eq of KMno4=number of eq of Br2
2 x 5 = nbr2 x 2
nbr2=5
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