Vikash Kumar
Last Activity: 11 Years ago
atomic mass of P =31
molecular weight of P4O10 = 284
apply unitary method
124 g of P is present in 284 g of P4O10
1 g of P is present in 284/124 g of P4O10
15 g of P is present in (284/124)*15=34.35 g(option 2) of P4O10
Thanks & Regards
Vikash Kumar,
askIITians Faculty
B.Tech, IIT Delhi