Flag Physical Chemistry> chemical-equilibrium...
question mark

naphthalene, a white solid used to make mothballs,has a vapour pressure of 0.10 mm hg at 27degree celcius. hence,Kp and Kc for the equilibrium are : C 10H8 (s) eqiulibrium with C10H8(g).

awaj hussain , 11 Years ago
Grade Upto college level
anser 3 Answers
Vikash Kumar

Last Activity: 11 Years ago

Kp = Kc (RT) ?n Where is number of moles of gaseous products – number of moles of gaseous reactants in the balanced chemical reaction.
so here there is only one gas molecule in product so Kp = .1 mm = 1.316 * 10-4 atm. (since 760mm=1 atm)
 ?n=1
so  Kc = Kp /RT = (1.316 * 10-4 )/(.0821 * 300) = 5.34 * 10-6 
Thanks & Regards
Vikash Kumar, 
askIITians Faculty
B.Tech, IIT Delhi

hemanth

Last Activity: 11 Years ago

p = Kc (RT) ?n Where is number of moles of gaseous products – number of moles of gaseous reactants in the balanced chemical reaction.
so here there is only one gas molecule in product so Kp = .1 mm = 1.316 * 10-4 atm. (since 760mm=1 atm)
 ?n=1
so  Kc = Kp /RT = (1.316 * 10-4 )/(.0821 * 300) = 5.34 * 10-6 
Thanks & Regards
Vikash Kumar, 
askIITians Faculty
B.Tech, IIT Delhi

Raunaq Mehta

Last Activity: 8 Years ago

p = Kc (RT) ?n Where is number of moles of gaseous products – number of moles of gaseous reactants in the balanced chemical reaction.so here there is only one gas molecule in product so Kp = .1 mm = 1.316 * 10-4 atm. (since 760mm=1 atm) ?n=1so Kc = Kp /RT = (1.316 * 10-4 )/(.0821 * 300) = 5.34 * 10-6

star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments