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The pK a of an acid having ionization constant 1 × 10 −5 is (A) 5 (B) −5 (C) −9 (D) 9



The pKa of an acid having ionization constant 1 × 10−5 is  


        (A)    5


        (B)    −5


        (C)    −9


        (D)    9


Grade:upto college level

1 Answers

Amit Saxena
35 Points
8 years ago

pKa = − log Ka (Ka = dissociation constant or ionization constant).

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