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The pKa of an acid having ionization constant 1 × 10−5 is(A) 5(B) −5(C) −9(D) 9

Amit Saxena , 11 Years ago
Grade upto college level
anser 1 Answers
Amit Saxena

Last Activity: 11 Years ago

pKa = − log Ka (Ka = dissociation constant or ionization constant).

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