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density of methanol- 0.793kg/L
what is its volume needed for making 2.5 L of its 0.25M solution?
KINDLY, EXPLAIN HOW TO SOLVE THIS.
First find the total number of moles
by using
MOLARITY*NFACTOR*VOLUME IS TOTAL NUMBER OF MOLES OF CH3OH.
now nfactor is 1
get the value of numer of moles.
find the mass of tis number of moles
ie.mass is equal to moles*32
now 1L of CH3OH is 0.793 g
therefore for x grams of methanol
volume required is
v=(x/0.793)litres.
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