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Calculate the mole fraction of benzene in solution containing 30% by mass in carbontetrachloride.
Let the total mass of the solution be 100 g and the mass of benzene be 30 g.∴Mass of carbon tetrachloride = (100 − 30)g= 70 gMolar mass of benzene (C6H6) = (6 × 12 + 6 × 1) g mol−1= 78 g mol−1
∴Number of moles of C6H6
= 0.3846 mol
Molar mass of carbon tetrachloride (CCl4) = 1 × 12 + 4 × 355= 154 g mol−1
∴Number of moles of CCl4= 0.4545 molThus, the mole fraction of C6H6 is given as:
= 0.458
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