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10ml of gaseous hydrogen on combustion gives 40ml of CO2 and 50ml of water then the hydrocarbon is- explain the solution(C4H10)

10ml of gaseous hydrogen on combustion gives 40ml of CO2 and 50ml of water then the hydrocarbon is-


explain the solution(C4H10)

Grade:12

2 Answers

ankitesh gupta
63 Points
7 years ago

CxHy + (x + y/4 )O2-----------xCO2  +  y/2  H2O                                                                                                                                                                                     applying eudiometry on hydrocarbon and products we get                                                                                                                                                             10/1  equal to 40/x and  50/0.5y                                                                                                                                                                     solving this get the value of x and y and get the molecular formula of the hydrocarbon                                                                                                                                        plzzzz approve if it helped you        

Shrey
19 Points
3 years ago
CxHy+(x+y4)O2→xCO2+y2H2OCxHyxy4O2xCO2y2H2ONow, gases occupying a volume at the same temperature and pressure have the same number of molecules. Hence, we can directly take out the ratio of moles that reacted:Gas volume Ratio of the hydrocarbon, CO2CO2 and H2OH2O is 10:40:50 or simplified, 1:4:5.Hence, the mole ratio of the hydrocarbon, CO2CO2 and H2OH2O is 1:4:5.Notice how x number of C in the hydrocarbon gives x mol of CO2CO2. That means, stoichiometrically 4 mol of CO2CO2 was given by...4 number of C! Hence,x = 4C4Hy+(4+y4)O2→4CO2+y2H2OC4Hy4y4O24CO2y2H2OSimilarly, y number of HH gives 5 mol of H2OH2O. For each two atoms of HH, you get 1 mol of H2OH2O. That means, 5=y25y2 or y = 10.Therefore, the hydrocarbon is C4H10C4H10.

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